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प्रश्न
Write the rationalisation factor of \[7 - 3\sqrt{5}\].
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उत्तर
The rationalizing factor of `a+sqrtb ` is `a- sqrtb `. Hence the rationalizing factor of `7-3sqrt5` is `7+3sqrt5`.
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संबंधित प्रश्न
Classify the following numbers as rational or irrational:
`2-sqrt5`
Express the following with rational denominator:
`1/(2sqrt5 - sqrt3)`
Simplify
`1/(2 + sqrt3) + 2/(sqrt5 - sqrt3) + 1/(2 - sqrt5)`
In the following determine rational numbers a and b:
`(sqrt11 - sqrt7)/(sqrt11 + sqrt7) = a - bsqrt77`
if `x= 3 + sqrt8`, find the value of `x^2 + 1/x^2`
Write the value of \[\left( 2 + \sqrt{3} \right) \left( 2 - \sqrt{3} \right) .\]
Simplify the following:
`root(4)(81) - 8root(3)(216) + 15root(5)(32) + sqrt(225)`
Rationalise the denominator of the following:
`sqrt(40)/sqrt(3)`
Find the value of a and b in the following:
`(7 + sqrt(5))/(7 - sqrt(5)) - (7 - sqrt(5))/(7 + sqrt(5)) = a + 7/11 sqrt(5)b`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`sqrt(2)/(2 + sqrt(2)`
