Advertisements
Advertisements
प्रश्न
Write the rationalisation factor of \[7 - 3\sqrt{5}\].
Advertisements
उत्तर
The rationalizing factor of `a+sqrtb ` is `a- sqrtb `. Hence the rationalizing factor of `7-3sqrt5` is `7+3sqrt5`.
APPEARS IN
संबंधित प्रश्न
Rationalise the denominator of the following:
`3/(2sqrt5)`
Rationalise the denominator of the following
`(sqrt3 + 1)/sqrt2`
if `x = (sqrt3 + 1)/2` find the value of `4x^2 +2x^2 - 8x + 7`
The rationalisation factor of \[\sqrt{3}\] is
After rationalising the denominator of `7/(3sqrt(3) - 2sqrt(2))`, we get the denominator as ______.
`root(4)root(3)(2^2)` equals to ______.
Simplify the following:
`3sqrt(3) + 2sqrt(27) + 7/sqrt(3)`
Simplify the following:
`root(4)(81) - 8root(3)(216) + 15root(5)(32) + sqrt(225)`
Rationalise the denominator of the following:
`(2 + sqrt(3))/(2 - sqrt(3))`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`(sqrt(10) - sqrt(5))/2`
