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प्रश्न
Write the rationalisation factor of \[7 - 3\sqrt{5}\].
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उत्तर
The rationalizing factor of `a+sqrtb ` is `a- sqrtb `. Hence the rationalizing factor of `7-3sqrt5` is `7+3sqrt5`.
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संबंधित प्रश्न
Recall, π is defined as the ratio of the circumference (say c) of a circle to its diameter (say d). That is, π = `c/d`. This seems to contradict the fact that π is irrational. How will you resolve this contradiction?
Rationalise the denominator of each of the following
`3/sqrt5`
Express each one of the following with rational denominator:
`(b^2)/(sqrt(a^2 + b^2) + a)`
In the following determine rational numbers a and b:
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\[\sqrt{10} \times \sqrt{15}\] is equal to
\[\sqrt[5]{6} \times \sqrt[5]{6}\] is equal to
Simplify:
`(1/27)^((-2)/3)`
