Advertisements
Advertisements
प्रश्न
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`6/sqrt(6)`
Advertisements
उत्तर
Let `E = 6/sqrt(6)`
For rationalising the denominator, multiplying numerator and denominator by `sqrt(6)`, we get
`E = 6/sqrt(6) xx sqrt(6)/sqrt(6)`
= `(6sqrt(6))/6`
= `sqrt(2) xx sqrt(3)` ...`["Put" sqrt(2) = 1.414 "and" sqrt(3) = 1.732]`
= `1.414 xx 1.732`
= 2.449
APPEARS IN
संबंधित प्रश्न
Simplify the following expression:
`(sqrt5 - sqrt2)(sqrt5 + sqrt2)`
Rationalise the denominator of the following
`(sqrt3 + 1)/sqrt2`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`2/sqrt3`
Express the following with rational denominator:
`30/(5sqrt3 - 3sqrt5)`
Express each one of the following with rational denominator:
`(b^2)/(sqrt(a^2 + b^2) + a)`
In the following determine rational numbers a and b:
`(sqrt3 - 1)/(sqrt3 + 1) = a - bsqrt3`
If x = \[\sqrt{5} + 2\],then \[x - \frac{1}{x}\] equals
The number obtained on rationalising the denominator of `1/(sqrt(7) - 2)` is ______.
`root(4)root(3)(2^2)` equals to ______.
Simplify:
`64^(-1/3)[64^(1/3) - 64^(2/3)]`
