Advertisements
Advertisements
प्रश्न
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`6/sqrt(6)`
Advertisements
उत्तर
Let `E = 6/sqrt(6)`
For rationalising the denominator, multiplying numerator and denominator by `sqrt(6)`, we get
`E = 6/sqrt(6) xx sqrt(6)/sqrt(6)`
= `(6sqrt(6))/6`
= `sqrt(2) xx sqrt(3)` ...`["Put" sqrt(2) = 1.414 "and" sqrt(3) = 1.732]`
= `1.414 xx 1.732`
= 2.449
APPEARS IN
संबंधित प्रश्न
Classify the following numbers as rational or irrational:
`2-sqrt5`
Simplify the following expressions:
`(sqrt5 - 2)(sqrt3 - sqrt5)`
Simplify the following expressions:
`(2sqrt5 + 3sqrt2)^2`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`3/sqrt10`
Express each one of the following with rational denominator:
`(b^2)/(sqrt(a^2 + b^2) + a)`
Rationales the denominator and simplify:
`(3 - sqrt2)/(3 + sqrt2)`
The rationalisation factor of \[\sqrt{3}\] is
Rationalise the denominator of the following:
`1/(sqrt7-2)`
After rationalising the denominator of `7/(3sqrt(3) - 2sqrt(2))`, we get the denominator as ______.
Rationalise the denominator of the following:
`(2 + sqrt(3))/(2 - sqrt(3))`
