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Question
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`6/sqrt(6)`
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Solution
Let `E = 6/sqrt(6)`
For rationalising the denominator, multiplying numerator and denominator by `sqrt(6)`, we get
`E = 6/sqrt(6) xx sqrt(6)/sqrt(6)`
= `(6sqrt(6))/6`
= `sqrt(2) xx sqrt(3)` ...`["Put" sqrt(2) = 1.414 "and" sqrt(3) = 1.732]`
= `1.414 xx 1.732`
= 2.449
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