Advertisements
Advertisements
Question
Rationalise the denominator of the following:
`sqrt(40)/sqrt(3)`
Advertisements
Solution
Let `E = sqrt(40)/sqrt(3)`
For rationalising the denominator, multiplying numerator and denominator by `sqrt(3)`,
`E = sqrt(40)/sqrt(3) xx sqrt(3)/sqrt(3)`
= `sqrt(40 xx 3)/(sqrt(3))^2`
= `sqrt(120)/3`
= `sqrt(2 xx 2 xx 2 xx 5 xx 3)/3`
= `2/3 sqrt(30)`
APPEARS IN
RELATED QUESTIONS
Rationalise the denominator of the following
`(sqrt3 + 1)/sqrt2`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`(sqrt10 + sqrt15)/sqrt2`
`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`(2 + sqrt3)/3`
Express the following with rational denominator:
`16/(sqrt41 - 5)`
Write the rationalisation factor of \[7 - 3\sqrt{5}\].
\[\sqrt{10} \times \sqrt{15}\] is equal to
\[\sqrt[5]{6} \times \sqrt[5]{6}\] is equal to
Rationalise the denominator of the following:
`1/(sqrt7-2)`
Simplify:
`(7sqrt(3))/(sqrt(10) + sqrt(3)) - (2sqrt(5))/(sqrt(6) + sqrt(5)) - (3sqrt(2))/(sqrt(15) + 3sqrt(2))`
Simplify:
`(256)^(-(4^((-3)/2))`
