Advertisements
Advertisements
Question
The simplest rationalising factor of \[2\sqrt{5}-\]\[\sqrt{3}\] is
Options
\[2\sqrt{5} + 3\]
\[2\sqrt{5} + \sqrt{3}\]
\[\sqrt{5} + \sqrt{3}\]
\[\sqrt{5} - \sqrt{3}\]
Advertisements
Solution
We know that rationalization factor for `asqrtb - sqrtc` is .`asqrtb +sqrtc` Hence rationalization factor of `2sqrt5-sqrt3`
APPEARS IN
RELATED QUESTIONS
Simplify:-
`2^(2/3). 2^(1/5)`
Simplify the following
`3(a^4b^3)^10xx5(a^2b^2)^3`
Solve the following equation for x:
`2^(3x-7)=256`
Assuming that x, y, z are positive real numbers, simplify the following:
`(sqrtx)^((-2)/3)sqrt(y^4)divsqrt(xy^((-1)/2))`
If 2x = 3y = 6-z, show that `1/x+1/y+1/z=0`
Solve the following equation:
`3^(x-1)xx5^(2y-3)=225`
If 24 × 42 =16x, then find the value of x.
If \[8^{x + 1}\] = 64 , what is the value of \[3^{2x + 1}\] ?
The value of \[\left\{ 8^{- 4/3} \div 2^{- 2} \right\}^{1/2}\] is
If \[\sqrt{13 - a\sqrt{10}} = \sqrt{8} + \sqrt{5}, \text { then a } =\]
