Advertisements
Advertisements
Question
If x = \[\frac{2}{3 + \sqrt{7}}\],then (x−3)2 =
Options
1
3
6
7
Advertisements
Solution
Given that: `x=2/(3+sqrt7)`
We know that rationalization factor for `3+sqrt7` is .`3-sqrt7` We will multiply numerator and denominator of the given expression `2/(3+sqrt7)` by `3 - sqrt7`, to get
`x = 2/(3+sqrt7) xx (3-sqrt7)/ (3-sqrt7)`
`= (2(3-sqrt7))/((3)^2 - (sqrt7)^2)`
`= (2(3-sqrt7))/(9-7) `
`= 3 - sqrt7`
Therefore,
`x-3 =-sqrt7`
On squaring both sides, we get
`(x-3)^2 = 7`
APPEARS IN
RELATED QUESTIONS
Assuming that x, y, z are positive real numbers, simplify the following:
`sqrt(x^3y^-2)`
Simplify:
`(sqrt2/5)^8div(sqrt2/5)^13`
If `27^x=9/3^x,` find x.
The value of \[\left\{ 2 - 3 (2 - 3 )^3 \right\}^3\] is
If x-2 = 64, then x1/3+x0 =
The value of \[\left\{ \left( 23 + 2^2 \right)^{2/3} + (140 - 19 )^{1/2} \right\}^2 ,\] is
If 102y = 25, then 10-y equals
If (16)2x+3 =(64)x+3, then 42x-2 =
The simplest rationalising factor of \[\sqrt[3]{500}\] is
If \[x = 7 + 4\sqrt{3}\] and xy =1, then \[\frac{1}{x^2} + \frac{1}{y^2} =\]
