Advertisements
Advertisements
प्रश्न
The simplest rationalising factor of \[2\sqrt{5}-\]\[\sqrt{3}\] is
विकल्प
\[2\sqrt{5} + 3\]
\[2\sqrt{5} + \sqrt{3}\]
\[\sqrt{5} + \sqrt{3}\]
\[\sqrt{5} - \sqrt{3}\]
Advertisements
उत्तर
We know that rationalization factor for `asqrtb - sqrtc` is .`asqrtb +sqrtc` Hence rationalization factor of `2sqrt5-sqrt3`
APPEARS IN
संबंधित प्रश्न
Simplify the following
`((4xx10^7)(6xx10^-5))/(8xx10^4)`
Prove that:
`9^(3/2)-3xx5^0-(1/81)^(-1/2)=15`
Prove that:
`(64/125)^(-2/3)+1/(256/625)^(1/4)+(sqrt25/root3 64)=65/16`
If ax = by = cz and b2 = ac, show that `y=(2zx)/(z+x)`
Find the value of x in the following:
`2^(5x)div2x=root5(2^20)`
Write the value of \[\sqrt[3]{7} \times \sqrt[3]{49} .\]
If (23)2 = 4x, then 3x =
If \[\sqrt{5^n} = 125\] then `5nsqrt64`=
\[\frac{5^{n + 2} - 6 \times 5^{n + 1}}{13 \times 5^n - 2 \times 5^{n + 1}}\] is equal to
Find:-
`125^(1/3)`
