Advertisements
Advertisements
प्रश्न
Find the value of x in the following:
`(sqrt(3/5))^(x+1)=125/27`
Advertisements
उत्तर
Given `(sqrt(3/5))^(x+1)=125/27`
`(sqrt(3/5))^(x+1)=(5/3)^3`
`rArr(3/5)^((x+1)/2)=(3/5)^-3`
On comparing we get,
`(x+1)/2=-3`
⇒ x + 1 = -3 x 2
⇒ x + 1 = -6
⇒ x = -6 - 1
⇒ x = -7
Hence, the value of x = -7.
APPEARS IN
संबंधित प्रश्न
Prove that:
`(a+b+c)/(a^-1b^-1+b^-1c^-1+c^-1a^-1)=abc`
Solve the following equation for x:
`2^(x+1)=4^(x-3)`
If a and b are different positive primes such that
`(a+b)^-1(a^-1+b^-1)=a^xb^y,` find x + y + 2.
If `2^x xx3^yxx5^z=2160,` find x, y and z. Hence, compute the value of `3^x xx2^-yxx5^-z.`
State the quotient law of exponents.
If 24 × 42 =16x, then find the value of x.
If 3x-1 = 9 and 4y+2 = 64, what is the value of \[\frac{x}{y}\] ?
The positive square root of \[7 + \sqrt{48}\] is
If \[x = \sqrt{6} + \sqrt{5}\],then \[x^2 + \frac{1}{x^2} - 2 =\]
Simplify:
`11^(1/2)/11^(1/4)`
