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Question
Find the value of x in the following:
`(sqrt(3/5))^(x+1)=125/27`
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Solution
Given `(sqrt(3/5))^(x+1)=125/27`
`(sqrt(3/5))^(x+1)=(5/3)^3`
`rArr(3/5)^((x+1)/2)=(3/5)^-3`
On comparing we get,
`(x+1)/2=-3`
⇒ x + 1 = -3 x 2
⇒ x + 1 = -6
⇒ x = -6 - 1
⇒ x = -7
Hence, the value of x = -7.
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