Advertisements
Advertisements
Question
The value of 64-1/3 (641/3-642/3), is
Options
1
\[\frac{1}{3}\]
-3
-2
Advertisements
Solution
Find the value of `64^(-1/3)(64^(1/3) - 64^(2/3)) `
So,
`64^(-1/3)(64^(1/3) - 64^(2/3)) = 2^(6 xx (-1)/3) ( 2^(6 xx (1)/3) - 2^(6 xx (2)/3) )`
`= 2^-2(2^2- 2^4)`
`= 2^-2(4-16)`
`64^(1/3) (64^(1/3) - 64^(2/3)) = 1/2^2 xx -12`
` = 1 /4 xx -12`
`= -3`
APPEARS IN
RELATED QUESTIONS
Solve the following equations for x:
`2^(2x)-2^(x+3)+2^4=0`
Assuming that x, y, z are positive real numbers, simplify the following:
`root5(243x^10y^5z^10)`
Prove that:
`(3^-3xx6^2xxsqrt98)/(5^2xxroot3(1/25)xx(15)^(-4/3)xx3^(1/3))=28sqrt2`
If `27^x=9/3^x,` find x.
Show that:
`((a+1/b)^mxx(a-1/b)^n)/((b+1/a)^mxx(b-1/a)^n)=(a/b)^(m+n)`
The value of x − yx-y when x = 2 and y = −2 is
If \[2^{- m} \times \frac{1}{2^m} = \frac{1}{4},\] then \[\frac{1}{14}\left\{ ( 4^m )^{1/2} + \left( \frac{1}{5^m} \right)^{- 1} \right\}\] is equal to
If \[\frac{5 - \sqrt{3}}{2 + \sqrt{3}} = x + y\sqrt{3}\] , then
If \[\sqrt{2} = 1 . 4142\] then \[\sqrt{\frac{\sqrt{2} - 1}{\sqrt{2} + 1}}\] is equal to
Find:-
`125^((-1)/3)`
