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प्रश्न
The value of 64-1/3 (641/3-642/3), is
विकल्प
1
\[\frac{1}{3}\]
-3
-2
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उत्तर
Find the value of `64^(-1/3)(64^(1/3) - 64^(2/3)) `
So,
`64^(-1/3)(64^(1/3) - 64^(2/3)) = 2^(6 xx (-1)/3) ( 2^(6 xx (1)/3) - 2^(6 xx (2)/3) )`
`= 2^-2(2^2- 2^4)`
`= 2^-2(4-16)`
`64^(1/3) (64^(1/3) - 64^(2/3)) = 1/2^2 xx -12`
` = 1 /4 xx -12`
`= -3`
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संबंधित प्रश्न
Find:-
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`((x^2y^2)/(a^2b^3))^n`
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`1/(1+x^(a-b))+1/(1+x^(b-a))=1`
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`2^(2x)-2^(x+3)+2^4=0`
Simplify:
`root5((32)^-3)`
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`((0.6)^0-(0.1)^-1)/((3/8)^-1(3/2)^3+((-1)/3)^-1)=(-3)/2`
Show that:
`(x^(a^2+b^2)/x^(ab))^(a+b)(x^(b^2+c^2)/x^(bc))^(b+c)(x^(c^2+a^2)/x^(ac))^(a+c)=x^(2(a^3+b^3+c^3))`
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Find:-
`32^(1/5)`
