Advertisements
Advertisements
प्रश्न
If \[\frac{x}{x^{1 . 5}} = 8 x^{- 1}\] and x > 0, then x =
विकल्प
\[\frac{\sqrt{2}}{4}\]
\[\sqrt[2]{2}\]
4
64
Advertisements
उत्तर
For `x /(x^1.5) = 8x^-1`, we have to find the value of x.
So,
`x^1 /(x^1.5) = 8x^-1`
`x ^(1-1.5) = 8x^-1`
`x ^(-0.5) = 2^3x^-1`
`(x^0.5) /x^-1= 2^3`
`x^(-5/10) /x^-1= 2^3`
`x^(-1/2+1)= 2^3`
`x^(-1/2+2/2)= 2^3`
`x^((-1+2)/2) = 2^3`
`x^(1/2) = 2^3`
By raising both sides to the power 2 we get
`x^(1/2xx2) = 2 ^(3xx2)`
`x^(1/2xx2) = 2 ^6`
`x^1 = 64`
The value of x is 64.
APPEARS IN
संबंधित प्रश्न
Simplify the following
`(a^(3n-9))^6/(a^(2n-4))`
If a = 3 and b = -2, find the values of :
ab + ba
Simplify:
`(0.001)^(1/3)`
Prove that:
`(2^(1/2)xx3^(1/3)xx4^(1/4))/(10^(-1/5)xx5^(3/5))div(3^(4/3)xx5^(-7/5))/(4^(-3/5)xx6)=10`
Show that:
`[{x^(a(a-b))/x^(a(a+b))}div{x^(b(b-a))/x^(b(b+a))}]^(a+b)=1`
If 3x = 5y = (75)z, show that `z=(xy)/(2x+y)`
Find the value of x in the following:
`(sqrt(3/5))^(x+1)=125/27`
If a, b, c are positive real numbers, then \[\sqrt{a^{- 1} b} \times \sqrt{b^{- 1} c} \times \sqrt{c^{- 1} a}\] is equal to
When simplified \[(256) {}^{- ( 4^{- 3/2} )}\] is
The simplest rationalising factor of \[\sqrt[3]{500}\] is
