Advertisements
Advertisements
प्रश्न
Solve the following equation for x:
`4^(x-1)xx(0.5)^(3-2x)=(1/8)^x`
Advertisements
उत्तर
`4^(x-1)xx(0.5)^(3-2x)=(1/8)^x`
`rArr(2^2)^(x-1)xx(1/2)^(3-2x)=(1/2^3)^x`
`rArr(2^2)^(x-1)xx(2^-1)^(3-2x)=(2^-3)^x`
`rArr2^(2x-2)xx2^(2x-3)=2^(-3x)`
`rArr2^(2x-2+2x-3)=2^(-3x)`
`rArr2^(4x-5)=2^(-3x)`
⇒ 4x - 5 = -3x
⇒ 4x + 3x = 5
⇒ 7x = 5
`rArr x = 5/7`
APPEARS IN
संबंधित प्रश्न
Assuming that x, y, z are positive real numbers, simplify the following:
`(sqrt2/sqrt3)^5(6/7)^2`
Simplify:
`(sqrt2/5)^8div(sqrt2/5)^13`
Prove that:
`((0.6)^0-(0.1)^-1)/((3/8)^-1(3/2)^3+((-1)/3)^-1)=(-3)/2`
Find the value of x in the following:
`5^(x-2)xx3^(2x-3)=135`
If `5^(3x)=125` and `10^y=0.001,` find x and y.
If 24 × 42 =16x, then find the value of x.
The value of \[\left\{ 2 - 3 (2 - 3 )^3 \right\}^3\] is
Find:-
`32^(2/5)`
Simplify:
`(1^3 + 2^3 + 3^3)^(1/2)`
Simplify:
`(3/5)^4 (8/5)^-12 (32/5)^6`
