Advertisements
Advertisements
प्रश्न
Solve the following equation for x:
`2^(3x-7)=256`
Advertisements
उत्तर
`2^(3x-7)=256`
`rArr2^(3x-7)=2^8`
⇒ 3x - 7 = 8
⇒ 3x = 8 + 7
⇒ 3x = 15
⇒ x = 15/3
⇒ x = 5
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Show that:
`[{x^(a(a-b))/x^(a(a+b))}div{x^(b(b-a))/x^(b(b+a))}]^(a+b)=1`
Show that:
`(3^a/3^b)^(a+b)(3^b/3^c)^(b+c)(3^c/3^a)^(c+a)=1`
Determine `(8x)^x,`If `9^(x+2)=240+9^x`
Write \[\left( 625 \right)^{- 1/4}\] in decimal form.
State the power law of exponents.
`(2/3)^x (3/2)^(2x)=81/16 `then x =
If 9x+2 = 240 + 9x, then x =
The value of \[\frac{\sqrt{48} + \sqrt{32}}{\sqrt{27} + \sqrt{18}}\] is
The value of \[\sqrt{3 - 2\sqrt{2}}\] is
Simplify:
`(9^(1/3) xx 27^(-1/2))/(3^(1/6) xx 3^(- 2/3))`
