Advertisements
Advertisements
प्रश्न
Find:-
`32^(1/5)`
Advertisements
उत्तर
We can write the given expression as follows
⇒ `32^(1/5) = (2^5)^(1/5)`
On simplifying
⇒ `32^(1/5) = 2^(5 xx 1/5)`
∴ `32^(1/5) = 2`
APPEARS IN
संबंधित प्रश्न
Simplify the following
`(4ab^2(-5ab^3))/(10a^2b^2)`
Prove that:
`(x^a/x^b)^(a^2+ab+b^2)xx(x^b/x^c)^(b^2+bc+c^2)xx(x^c/x^a)^(c^2+ca+a^2)=1`
Simplify:
`root3((343)^-2)`
Show that:
`(x^(a^2+b^2)/x^(ab))^(a+b)(x^(b^2+c^2)/x^(bc))^(b+c)(x^(c^2+a^2)/x^(ac))^(a+c)=x^(2(a^3+b^3+c^3))`
If `x = a^(m + n), y = a^(n + l)` and `z = a^(l + m),` prove that `x^my^nz^l = x^ny^lz^m`
State the product law of exponents.
If \[\frac{3^{2x - 8}}{225} = \frac{5^3}{5^x},\] then x =
If 10x = 64, what is the value of \[{10}^\frac{x}{2} + 1 ?\]
The value of \[\frac{\sqrt{48} + \sqrt{32}}{\sqrt{27} + \sqrt{18}}\] is
Simplify:
`(9^(1/3) xx 27^(-1/2))/(3^(1/6) xx 3^(- 2/3))`
