Advertisements
Advertisements
Question
Find:-
`32^(1/5)`
Sum
Advertisements
Solution
We can write the given expression as follows
⇒ `32^(1/5) = (2^5)^(1/5)`
On simplifying
⇒ `32^(1/5) = 2^(5 xx 1/5)`
∴ `32^(1/5) = 2`
shaalaa.com
Is there an error in this question or solution?
Chapter 1: Number Systems - EXERCISE 1.5 [Page 23]
APPEARS IN
RELATED QUESTIONS
Simplify the following
`3(a^4b^3)^10xx5(a^2b^2)^3`
If a = 3 and b = -2, find the values of :
(a + b)ab
Assuming that x, y, z are positive real numbers, simplify the following:
`root5(243x^10y^5z^10)`
Prove that:
`(1/4)^-2-3xx8^(2/3)xx4^0+(9/16)^(-1/2)=16/3`
Prove that:
`(3^-3xx6^2xxsqrt98)/(5^2xxroot3(1/25)xx(15)^(-4/3)xx3^(1/3))=28sqrt2`
Prove that:
`((0.6)^0-(0.1)^-1)/((3/8)^-1(3/2)^3+((-1)/3)^-1)=(-3)/2`
If 3x = 5y = (75)z, show that `z=(xy)/(2x+y)`
If `x=2^(1/3)+2^(2/3),` Show that x3 - 6x = 6
If o <y <x, which statement must be true?
Simplify:
`11^(1/2)/11^(1/4)`
