Advertisements
Advertisements
प्रश्न
Find:-
`32^(1/5)`
बेरीज
Advertisements
उत्तर
We can write the given expression as follows
⇒ `32^(1/5) = (2^5)^(1/5)`
On simplifying
⇒ `32^(1/5) = 2^(5 xx 1/5)`
∴ `32^(1/5) = 2`
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: Number Systems - EXERCISE 1.5 [पृष्ठ २३]
APPEARS IN
संबंधित प्रश्न
If a = 3 and b = -2, find the values of :
aa + bb
Assuming that x, y, z are positive real numbers, simplify the following:
`root5(243x^10y^5z^10)`
If `27^x=9/3^x,` find x.
Find the value of x in the following:
`2^(5x)div2x=root5(2^20)`
If `2^x xx3^yxx5^z=2160,` find x, y and z. Hence, compute the value of `3^x xx2^-yxx5^-z.`
The product of the square root of x with the cube root of x is
Which of the following is (are) not equal to \[\left\{ \left( \frac{5}{6} \right)^{1/5} \right\}^{- 1/6}\] ?
If (23)2 = 4x, then 3x =
If 102y = 25, then 10-y equals
Find:-
`125^((-1)/3)`
