Advertisements
Advertisements
प्रश्न
If `27^x=9/3^x,` find x.
Advertisements
उत्तर
We are given `27^x=9/3^x`
We have to find the value of x
Since `(3^3)^x=3^2/3^x`
By using the law of exponents `a^m/a^n=a^(m-n)` we get,
`3^(3x)=3^(2-x)`
on equating the exponents we get,
3x = 2 - x
3x + x = 2
4x = 2
x = 2/4
x = 1/2
Hence, `x=1/2`
APPEARS IN
संबंधित प्रश्न
Simplify:-
`2^(2/3). 2^(1/5)`
Simplify the following
`((x^2y^2)/(a^2b^3))^n`
Prove that:
`(a^-1+b^-1)^-1=(ab)/(a+b)`
Solve the following equation:
`8^(x+1)=16^(y+2)` and, `(1/2)^(3+x)=(1/4)^(3y)`
If a and b are different positive primes such that
`((a^-1b^2)/(a^2b^-4))^7div((a^3b^-5)/(a^-2b^3))=a^xb^y,` find x and y.
The square root of 64 divided by the cube root of 64 is
If a, b, c are positive real numbers, then \[\sqrt[5]{3125 a^{10} b^5 c^{10}}\] is equal to
If \[\frac{x}{x^{1 . 5}} = 8 x^{- 1}\] and x > 0, then x =
If o <y <x, which statement must be true?
The simplest rationalising factor of \[\sqrt{3} + \sqrt{5}\] is ______.
