Advertisements
Advertisements
Question
If `27^x=9/3^x,` find x.
Advertisements
Solution
We are given `27^x=9/3^x`
We have to find the value of x
Since `(3^3)^x=3^2/3^x`
By using the law of exponents `a^m/a^n=a^(m-n)` we get,
`3^(3x)=3^(2-x)`
on equating the exponents we get,
3x = 2 - x
3x + x = 2
4x = 2
x = 2/4
x = 1/2
Hence, `x=1/2`
APPEARS IN
RELATED QUESTIONS
Simplify the following
`(4ab^2(-5ab^3))/(10a^2b^2)`
Prove that:
`1/(1 + x^(b - a) + x^(c - a)) + 1/(1 + x^(a - b) + x^(c - b)) + 1/(1 + x^(b - c) + x^(a - c)) = 1`
Solve the following equation for x:
`2^(5x+3)=8^(x+3)`
Solve the following equation for x:
`4^(2x)=1/32`
Show that:
`(x^(1/(a-b)))^(1/(a-c))(x^(1/(b-c)))^(1/(b-a))(x^(1/(c-a)))^(1/(c-b))=1`
Write \[\left( \frac{1}{9} \right)^{- 1/2} \times (64 )^{- 1/3}\] as a rational number.
The value of x − yx-y when x = 2 and y = −2 is
The value of \[\left\{ 8^{- 4/3} \div 2^{- 2} \right\}^{1/2}\] is
If \[x + \sqrt{15} = 4,\] then \[x + \frac{1}{x}\] =
Find:-
`125^(1/3)`
