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Question
If `27^x=9/3^x,` find x.
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Solution
We are given `27^x=9/3^x`
We have to find the value of x
Since `(3^3)^x=3^2/3^x`
By using the law of exponents `a^m/a^n=a^(m-n)` we get,
`3^(3x)=3^(2-x)`
on equating the exponents we get,
3x = 2 - x
3x + x = 2
4x = 2
x = 2/4
x = 1/2
Hence, `x=1/2`
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