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Question
Solve the following equation:
`3^(x+1)=27xx3^4`
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Solution
`3^(x+1)=27xx3^4`
`rArr3^(x+1)=3^3xx3^4`
`rArr3^(x+1)=3^(3+4)`
`rArr3^(x+1)=3^7`
⇒ x + 1 = 7
⇒ x = 7 - 1
⇒ x = 6
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