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Question
If `5^(3x)=125` and `10^y=0.001,` find x and y.
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Solution
It is given that `5^(3x)=125` and `10^y=0.001`.
Now,
`5^(3x)=125`
`rArr5^(3x)=5^3`
`rArr3x = 3`
x = 1
And,
`10^y=0.001`
`rArr10^y=1/1000`
`rArr10^y=10^-3`
⇒ y = -3
hence, the value of x and yare 1 and -3, respectively.
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