Advertisements
Advertisements
Question
Solve the following equations for x:
`3^(2x+4)+1=2.3^(x+2)`
Advertisements
Solution
`3^(2x+4)+1=2.3^(x+2)`
`rArr(3^(x+2))^2-2.3^(x+2)+1=0`
`rArr(3^(x+2)-1)^2=0`
`rArr3^(x+2)-1=0`
`rArr3^(x+2)=1`
`rArr3^(x+2)=3^0`
⇒ x + 2 = 0
⇒ x = -2
APPEARS IN
RELATED QUESTIONS
Prove that:
`(x^a/x^b)^cxx(x^b/x^c)^axx(x^c/x^a)^b=1`
Given `4725=3^a5^b7^c,` find
(i) the integral values of a, b and c
(ii) the value of `2^-a3^b7^c`
Assuming that x, y, z are positive real numbers, simplify the following:
`sqrt(x^3y^-2)`
Simplify:
`((5^-1xx7^2)/(5^2xx7^-4))^(7/2)xx((5^-2xx7^3)/(5^3xx7^-5))^(-5/2)`
Simplify:
`(x^(a+b)/x^c)^(a-b)(x^(b+c)/x^a)^(b-c)(x^(c+a)/x^b)^(c-a)`
Write the value of \[\sqrt[3]{7} \times \sqrt[3]{49} .\]
The seventh root of x divided by the eighth root of x is
If 102y = 25, then 10-y equals
If g = `t^(2/3) + 4t^(-1/2)`, what is the value of g when t = 64?
\[\frac{5^{n + 2} - 6 \times 5^{n + 1}}{13 \times 5^n - 2 \times 5^{n + 1}}\] is equal to
