Advertisements
Advertisements
प्रश्न
Solve the following equations for x:
`3^(2x+4)+1=2.3^(x+2)`
Advertisements
उत्तर
`3^(2x+4)+1=2.3^(x+2)`
`rArr(3^(x+2))^2-2.3^(x+2)+1=0`
`rArr(3^(x+2)-1)^2=0`
`rArr3^(x+2)-1=0`
`rArr3^(x+2)=1`
`rArr3^(x+2)=3^0`
⇒ x + 2 = 0
⇒ x = -2
APPEARS IN
संबंधित प्रश्न
Prove that:
`1/(1+x^(a-b))+1/(1+x^(b-a))=1`
Assuming that x, y, z are positive real numbers, simplify the following:
`sqrt(x^3y^-2)`
Assuming that x, y, z are positive real numbers, simplify the following:
`(sqrtx)^((-2)/3)sqrt(y^4)divsqrt(xy^((-1)/2))`
Prove that:
`((0.6)^0-(0.1)^-1)/((3/8)^-1(3/2)^3+((-1)/3)^-1)=(-3)/2`
If `x = a^(m + n), y = a^(n + l)` and `z = a^(l + m),` prove that `x^my^nz^l = x^ny^lz^m`
If 24 × 42 =16x, then find the value of x.
For any positive real number x, write the value of \[\left\{ \left( x^a \right)^b \right\}^\frac{1}{ab} \left\{ \left( x^b \right)^c \right\}^\frac{1}{bc} \left\{ \left( x^c \right)^a \right\}^\frac{1}{ca}\]
If 102y = 25, then 10-y equals
The value of \[\frac{\sqrt{48} + \sqrt{32}}{\sqrt{27} + \sqrt{18}}\] is
Find:-
`125^((-1)/3)`
