Advertisements
Advertisements
प्रश्न
If 49392 = a4b2c3, find the values of a, b and c, where a, b and c are different positive primes.
Advertisements
उत्तर
First find out the prime factorisation of 49392.
It can be observed that 49392 can be written as `2^4xx3^2xx7^3,` where 2, 3 and 7 are positive primes.
`therefore49392=2^4 3^2 7^3=a^4b^2c^3`
⇒ a = 2, b = 3, c = 7
APPEARS IN
संबंधित प्रश्न
Simplify the following
`(2x^-2y^3)^3`
Simplify the following
`((4xx10^7)(6xx10^-5))/(8xx10^4)`
Solve the following equation for x:
`2^(3x-7)=256`
Prove that:
`(2^n+2^(n-1))/(2^(n+1)-2^n)=3/2`
Determine `(8x)^x,`If `9^(x+2)=240+9^x`
Solve the following equation:
`sqrt(a/b)=(b/a)^(1-2x),` where a and b are distinct primes.
For any positive real number x, find the value of \[\left( \frac{x^a}{x^b} \right)^{a + b} \times \left( \frac{x^b}{x^c} \right)^{b + c} \times \left( \frac{x^c}{x^a} \right)^{c + a}\].
If a, b, c are positive real numbers, then \[\sqrt{a^{- 1} b} \times \sqrt{b^{- 1} c} \times \sqrt{c^{- 1} a}\] is equal to
If a, b, c are positive real numbers, then \[\sqrt[5]{3125 a^{10} b^5 c^{10}}\] is equal to
If g = `t^(2/3) + 4t^(-1/2)`, what is the value of g when t = 64?
