Advertisements
Advertisements
प्रश्न
If 49392 = a4b2c3, find the values of a, b and c, where a, b and c are different positive primes.
Advertisements
उत्तर
First find out the prime factorisation of 49392.

It can be observed that 49392 can be written as `2^4xx3^2xx7^3,` where 2, 3 and 7 are positive primes.
`therefore49392=2^4 3^2 7^3=a^4b^2c^3`
⇒ a = 2, b = 3, c = 7
APPEARS IN
संबंधित प्रश्न
Simplify the following
`(4ab^2(-5ab^3))/(10a^2b^2)`
If `27^x=9/3^x,` find x.
If `x=2^(1/3)+2^(2/3),` Show that x3 - 6x = 6
Solve the following equation:
`3^(x-1)xx5^(2y-3)=225`
If 1176 = `2^axx3^bxx7^c,` find the values of a, b and c. Hence, compute the value of `2^axx3^bxx7^-c` as a fraction.
Write the value of \[\left\{ 5( 8^{1/3} + {27}^{1/3} )^3 \right\}^{1/4} . \]
When simplified \[\left( - \frac{1}{27} \right)^{- 2/3}\] is
If \[4x - 4 x^{- 1} = 24,\] then (2x)x equals
If \[x + \sqrt{15} = 4,\] then \[x + \frac{1}{x}\] =
Find:-
`32^(2/5)`
