Advertisements
Advertisements
प्रश्न
If 3x-1 = 9 and 4y+2 = 64, what is the value of \[\frac{x}{y}\] ?
Advertisements
उत्तर
We have to find the value of `x/y` for `3^(x-1) = 9.4^(y+2) = 64`
So,
`3^(x-4) = 3 ^2`
By equating the exponent we get
x-1=2
x=2+1
x=3
Let’s take `4^(y+2) = 64`
`4^(y+2) = 4^3`
By equating the exponent we get
y+2 = 3
y=3-2
y=1
By substituting x=3,y=1 in `x/y` we get `3/1`
Hence the value of `x/y` is 3.
APPEARS IN
संबंधित प्रश्न
Prove that:
`(a+b+c)/(a^-1b^-1+b^-1c^-1+c^-1a^-1)=abc`
Simplify the following:
`(5^(n+3)-6xx5^(n+1))/(9xx5^x-2^2xx5^n)`
Assuming that x, y, z are positive real numbers, simplify the following:
`root5(243x^10y^5z^10)`
Prove that:
`(64/125)^(-2/3)+1/(256/625)^(1/4)+(sqrt25/root3 64)=65/16`
Solve the following equation:
`3^(x+1)=27xx3^4`
Write \[\left( \frac{1}{9} \right)^{- 1/2} \times (64 )^{- 1/3}\] as a rational number.
If (x − 1)3 = 8, What is the value of (x + 1)2 ?
The value of \[\left\{ 8^{- 4/3} \div 2^{- 2} \right\}^{1/2}\] is
If a, m, n are positive ingegers, then \[\left\{ \sqrt[m]{\sqrt[n]{a}} \right\}^{mn}\] is equal to
If \[x = \frac{\sqrt{5} + \sqrt{3}}{\sqrt{5} - \sqrt{3}}\] and \[y = \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} + \sqrt{3}}\] then x + y +xy=
