Advertisements
Advertisements
प्रश्न
If 3x-1 = 9 and 4y+2 = 64, what is the value of \[\frac{x}{y}\] ?
Advertisements
उत्तर
We have to find the value of `x/y` for `3^(x-1) = 9.4^(y+2) = 64`
So,
`3^(x-4) = 3 ^2`
By equating the exponent we get
x-1=2
x=2+1
x=3
Let’s take `4^(y+2) = 64`
`4^(y+2) = 4^3`
By equating the exponent we get
y+2 = 3
y=3-2
y=1
By substituting x=3,y=1 in `x/y` we get `3/1`
Hence the value of `x/y` is 3.
APPEARS IN
संबंधित प्रश्न
If a = 3 and b = -2, find the values of :
aa + bb
Assuming that x, y, z are positive real numbers, simplify the following:
`(sqrt(x^-3))^5`
Show that:
`1/(1+x^(a-b))+1/(1+x^(b-a))=1`
If `3^(4x) = (81)^-1` and `10^(1/y)=0.0001,` find the value of ` 2^(-x+4y)`.
If a and b are distinct primes such that `root3 (a^6b^-4)=a^xb^(2y),` find x and y.
If a and b are different positive primes such that
`(a+b)^-1(a^-1+b^-1)=a^xb^y,` find x + y + 2.
State the quotient law of exponents.
Which one of the following is not equal to \[\left( \frac{100}{9} \right)^{- 3/2}\]?
If \[x = \frac{\sqrt{5} + \sqrt{3}}{\sqrt{5} - \sqrt{3}}\] and \[y = \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} + \sqrt{3}}\] then x + y +xy=
\[\frac{1}{\sqrt{9} - \sqrt{8}}\] is equal to
