Question

If 3^x-1 = 9 and 4^y+2 = 64, what is the value  of \[\frac{x}{y}\] ?

Answer 1

We have to find the value of `x/y` for `3^(x-1) = 9.4^(y+2) = 64` 

So,

`3^(x-4) = 3 ^2`

By equating the exponent we get

x-1=2

x=2+1

x=3

Let’s take `4^(y+2) = 64`

`4^(y+2) = 4^3`

By equating the exponent we get

y+2 = 3

y=3-2

y=1

By substituting x=3,y=1 in `x/y` we get  `3/1`

Hence the value of `x/y` is  3.