Advertisements
Advertisements
Question
Solve the following equation:
`4^(x-1)xx(0.5)^(3-2x)=(1/8)^x`
Advertisements
Solution
`4^(x-1)xx(0.5)^(3-2x)=(1/8)^x`
`rArr(2^2)^(x-1)xx(1/2)^(3-2x)=(1/2^3)^x`
`rArr(2)^(2x-2)xx(2)^(-(3-2x))=(2)(-3x)`
`rArr(2)^(2x-2-3+2x)=(2)^(-3x)`
⇒ 4x - 5 = -3x
⇒ 4x + 3x = 5
⇒ 7x = 5
⇒ x = 5/7
APPEARS IN
RELATED QUESTIONS
If a = 3 and b = -2, find the values of :
ab + ba
Simplify the following:
`(5^(n+3)-6xx5^(n+1))/(9xx5^x-2^2xx5^n)`
If `2^x xx3^yxx5^z=2160,` find x, y and z. Hence, compute the value of `3^x xx2^-yxx5^-z.`
Write the value of \[\sqrt[3]{125 \times 27}\].
If a, b, c are positive real numbers, then \[\sqrt[5]{3125 a^{10} b^5 c^{10}}\] is equal to
If 102y = 25, then 10-y equals
If \[\sqrt{2^n} = 1024,\] then \[{3^2}^\left( \frac{n}{4} - 4 \right) =\]
If x = \[\frac{2}{3 + \sqrt{7}}\],then (x−3)2 =
If \[x + \sqrt{15} = 4,\] then \[x + \frac{1}{x}\] =
If x = \[\sqrt[3]{2 + \sqrt{3}}\] , then \[x^3 + \frac{1}{x^3} =\]
