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प्रश्न
Solve the following equation:
`4^(x-1)xx(0.5)^(3-2x)=(1/8)^x`
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उत्तर
`4^(x-1)xx(0.5)^(3-2x)=(1/8)^x`
`rArr(2^2)^(x-1)xx(1/2)^(3-2x)=(1/2^3)^x`
`rArr(2)^(2x-2)xx(2)^(-(3-2x))=(2)(-3x)`
`rArr(2)^(2x-2-3+2x)=(2)^(-3x)`
⇒ 4x - 5 = -3x
⇒ 4x + 3x = 5
⇒ 7x = 5
⇒ x = 5/7
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