Advertisements
Advertisements
प्रश्न
Simplify the following
`(4ab^2(-5ab^3))/(10a^2b^2)`
Advertisements
उत्तर
`(4ab^2(-5ab^3))/(10a^2b^2)`
`=(4xxaxxb^2xx(-5)xxaxxb^3)/(10a^2b^2)`
`=(-20xxa^1xxa^1xxb^2xxb^3)/(10a^2b^2)`
`=(-20xxa^(1+1)xxb^(2+3))/(10a^2b^2)`
`=-2xxa^2xxb^5xxa^-2xxb^-2`
`=-2xxa^(2+(-2))xxb^(5+(-2))`
`=-2xxa^0xxb^3`
`=-2b^3`
APPEARS IN
संबंधित प्रश्न
Prove that:
`1/(1+x^(a-b))+1/(1+x^(b-a))=1`
Prove that:
`(2^n+2^(n-1))/(2^(n+1)-2^n)=3/2`
Show that:
`(x^(a^2+b^2)/x^(ab))^(a+b)(x^(b^2+c^2)/x^(bc))^(b+c)(x^(c^2+a^2)/x^(ac))^(a+c)=x^(2(a^3+b^3+c^3))`
If a and b are different positive primes such that
`((a^-1b^2)/(a^2b^-4))^7div((a^3b^-5)/(a^-2b^3))=a^xb^y,` find x and y.
If (23)2 = 4x, then 3x =
If x-2 = 64, then x1/3+x0 =
Which one of the following is not equal to \[\left( \frac{100}{9} \right)^{- 3/2}\]?
If x = 2 and y = 4, then \[\left( \frac{x}{y} \right)^{x - y} + \left( \frac{y}{x} \right)^{y - x} =\]
The value of 64-1/3 (641/3-642/3), is
The simplest rationalising factor of \[\sqrt[3]{500}\] is
