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प्रश्न
Simplify:-
`(1/3^3)^7`
बेरीज
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उत्तर
We can write the given expression as follows
⇒ `(1/3^3)^7 = (3^-3)^7`
= `3^(-3 xx 7)`
On simplifying
∴ `(1/3^3)^7 = 3^-21`
= `(1/3^3)^7 =1/3^21`
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पाठ 1: Number Systems - EXERCISE 1.5 [पृष्ठ २३]
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संबंधित प्रश्न
Find:-
`64^(1/2)`
Prove that:
`(x^a/x^b)^(a^2+ab+b^2)xx(x^b/x^c)^(b^2+bc+c^2)xx(x^c/x^a)^(c^2+ca+a^2)=1`
Simplify:
`root5((32)^-3)`
Prove that:
`sqrt(1/4)+(0.01)^(-1/2)-(27)^(2/3)=3/2`
If 2x = 3y = 6-z, show that `1/x+1/y+1/z=0`
If `3^(4x) = (81)^-1` and `10^(1/y)=0.0001,` find the value of ` 2^(-x+4y)`.
Solve the following equation:
`4^(2x)=(root3 16)^(-6/y)=(sqrt8)^2`
If a and b are distinct primes such that `root3 (a^6b^-4)=a^xb^(2y),` find x and y.
Find:-
`125^(1/3)`
Simplify:
`7^(1/2) . 8^(1/2)`
