Advertisements
Advertisements
प्रश्न
The value of \[\left\{ 8^{- 4/3} \div 2^{- 2} \right\}^{1/2}\] is
पर्याय
\[\frac{1}{2}\]
2
\[\frac{1}{4}\]
4
Advertisements
उत्तर
Find the value of `{8^ (- 4/3)÷ 2^-2}^(1/2)`
`{8^ (- 4/3)÷ 2^-2}^(1/2) = {2^(3x-4/3)÷2^-2 }^(1/2)`
`= {2^(3x(-4)/3)÷2^-2 }^(1/2)`
`= {2^-4 ÷2^-2 }^(1/2)`
`{8^ (- 4/3)÷ 2^-2}^(1/2) = {2^(-4xx1/2)÷ 2^(-2xx1/2)}`
`= {2^(-4xx1/2)÷ 2^(-2xx1/2)}`
` = {2^2 ÷ 2^-1}`
` = {(1/2^2)/(1/2)}`
`{8^ (- 4/3)÷ 2^-2}^(1/2) = {1/(2xx2) xx 2/1}`
=`{1/(2xx2) xx 2/1}`
= `1/2`
APPEARS IN
संबंधित प्रश्न
Assuming that x, y, z are positive real numbers, simplify the following:
`(x^((-2)/3)y^((-1)/2))^2`
Prove that:
`sqrt(1/4)+(0.01)^(-1/2)-(27)^(2/3)=3/2`
Show that:
`1/(1+x^(a-b))+1/(1+x^(b-a))=1`
Show that:
`(3^a/3^b)^(a+b)(3^b/3^c)^(b+c)(3^c/3^a)^(c+a)=1`
Find the value of x in the following:
`(root3 4)^(2x+1/2)=1/32`
Solve the following equation:
`4^(2x)=(root3 16)^(-6/y)=(sqrt8)^2`
If `a=x^(m+n)y^l, b=x^(n+l)y^m` and `c=x^(l+m)y^n,` Prove that `a^(m-n)b^(n-l)c^(l-m)=1`
If \[\frac{3^{2x - 8}}{225} = \frac{5^3}{5^x},\] then x =
The value of 64-1/3 (641/3-642/3), is
If \[\frac{5 - \sqrt{3}}{2 + \sqrt{3}} = x + y\sqrt{3}\] , then
