Advertisements
Advertisements
प्रश्न
Simplify:
`(3/5)^4 (8/5)^-12 (32/5)^6`
Advertisements
उत्तर
`(3/5)^4 (8/5)^-12 (32/5)^6 = 3^4/5^4 xx (5/2^3)^12 xx (2^5/5)^6` ...`(∵ a^-1 = 1/a)`
= `3^4/5^4 xx 5^12/2^36 xx 2^30/5^6` ...[∵ (am)n = amn]
= `(3^4 xx 5^(12 - 4 - 6))/(2^(36 - 30))` ...`[∵ a^m/a^n = a^(m - n)]`
= `3^4/2^6 xx 5^2`
= `(81 xx 25)/64`
= `2025/64`
APPEARS IN
संबंधित प्रश्न
Simplify the following
`((x^2y^2)/(a^2b^3))^n`
Prove that:
`(a^-1+b^-1)^-1=(ab)/(a+b)`
Prove that:
`((0.6)^0-(0.1)^-1)/((3/8)^-1(3/2)^3+((-1)/3)^-1)=(-3)/2`
Show that:
`[{x^(a(a-b))/x^(a(a+b))}div{x^(b(b-a))/x^(b(b+a))}]^(a+b)=1`
If 24 × 42 =16x, then find the value of x.
When simplified \[\left( - \frac{1}{27} \right)^{- 2/3}\] is
(256)0.16 × (256)0.09
If \[4x - 4 x^{- 1} = 24,\] then (2x)x equals
If x = \[\frac{2}{3 + \sqrt{7}}\],then (x−3)2 =
Find:-
`32^(2/5)`
