Advertisements
Advertisements
प्रश्न
The value of \[\left\{ \left( 23 + 2^2 \right)^{2/3} + (140 - 19 )^{1/2} \right\}^2 ,\] is
पर्याय
196
289
324
400
Advertisements
उत्तर
We have to find the value of `{(23+2^2)^(2/3)+ (140- 19 )^(1/2) }^2`
`{(23+2^2)^(2/3)+ (140- 19 )^(1/2) }^2 = {(23+4)^(2/3)+ (121)^(1/2) }^2`
= `{(27)^(2/3)+ (121)^(1/2) }^2`
`={(3^3)^(2/3)+ (11^2)^(1/2) }^2`
`{(23+2^2)^(2/3)+ (140- 19 )^(1/2) }^2`= ` {3^(3 xx2/3) +11
^( 2xx 1/2)}^2`
` = {3^(3 xx2/3) +11^( 2xx 1/2)}^2`
= `{3^2 + 11}^2`
`⇒ {(23+2^2)^(2/3)+ (140- 19 )^(1/2) }^2 = {9+11}^2`
By using the identity `(a+b)^2 = a^2 +2ab +b^2` we get,
`= 9 xx 9 +2 xx 9 xx 11 + 11 xx 11`
`= 81 +198 +121`
`= 400`
APPEARS IN
संबंधित प्रश्न
Simplify:-
`2^(2/3). 2^(1/5)`
Solve the following equation for x:
`2^(x+1)=4^(x-3)`
Solve the following equations for x:
`3^(2x+4)+1=2.3^(x+2)`
Assuming that x, y, z are positive real numbers, simplify the following:
`(sqrt2/sqrt3)^5(6/7)^2`
Prove that:
`sqrt(3xx5^-3)divroot3(3^-1)sqrt5xxroot6(3xx5^6)=3/5`
If 2x = 3y = 6-z, show that `1/x+1/y+1/z=0`
If `x=2^(1/3)+2^(2/3),` Show that x3 - 6x = 6
If `3^(4x) = (81)^-1` and `10^(1/y)=0.0001,` find the value of ` 2^(-x+4y)`.
State the product law of exponents.
If \[\sqrt{5^n} = 125\] then `5nsqrt64`=
