Advertisements
Advertisements
प्रश्न
(256)0.16 × (256)0.09
पर्याय
4
16
64
256.25
Advertisements
उत्तर
We have to find the value of `(256)^0.16 xx (256)^0.09`So,
By using law of rational exponents
`a^m xx a^n = a^(m+n)` we get
`(256)^0.16 xx (256)^0.09 = (256)^0.16 xx (256)^0.09`
=`(256)^(0.16+0.09)`
= `256^(0.25)`
=`(256)^(25/100)`
`(256)^0.16 xx (256)^0.09 = 2^(8 xx 25/100)`
= `2^(8 xx 25/100)`
` = 2^(8 xx 1/4)`
` = 2^(8 xx 1/4)`
= 4
The value of `(256)^0.16 xx (256)^0.09 `is 4
APPEARS IN
संबंधित प्रश्न
Solve the following equation for x:
`2^(x+1)=4^(x-3)`
Prove that:
`sqrt(3xx5^-3)divroot3(3^-1)sqrt5xxroot6(3xx5^6)=3/5`
Show that:
`[{x^(a(a-b))/x^(a(a+b))}div{x^(b(b-a))/x^(b(b+a))}]^(a+b)=1`
Find the value of x in the following:
`(3/5)^x(5/3)^(2x)=125/27`
Find the value of x in the following:
`5^(x-2)xx3^(2x-3)=135`
Find the value of x in the following:
`5^(2x+3)=1`
Show that:
`((a+1/b)^mxx(a-1/b)^n)/((b+1/a)^mxx(b-1/a)^n)=(a/b)^(m+n)`
When simplified \[( x^{- 1} + y^{- 1} )^{- 1}\] is equal to
If \[\frac{x}{x^{1 . 5}} = 8 x^{- 1}\] and x > 0, then x =
If x = \[\frac{2}{3 + \sqrt{7}}\],then (x−3)2 =
