Advertisements
Advertisements
प्रश्न
(256)0.16 × (256)0.09
विकल्प
4
16
64
256.25
Advertisements
उत्तर
We have to find the value of `(256)^0.16 xx (256)^0.09`So,
By using law of rational exponents
`a^m xx a^n = a^(m+n)` we get
`(256)^0.16 xx (256)^0.09 = (256)^0.16 xx (256)^0.09`
=`(256)^(0.16+0.09)`
= `256^(0.25)`
=`(256)^(25/100)`
`(256)^0.16 xx (256)^0.09 = 2^(8 xx 25/100)`
= `2^(8 xx 25/100)`
` = 2^(8 xx 1/4)`
` = 2^(8 xx 1/4)`
= 4
The value of `(256)^0.16 xx (256)^0.09 `is 4
APPEARS IN
संबंधित प्रश्न
Prove that:
`1/(1 + x^(b - a) + x^(c - a)) + 1/(1 + x^(a - b) + x^(c - b)) + 1/(1 + x^(b - c) + x^(a - c)) = 1`
Prove that:
`(2^(1/2)xx3^(1/3)xx4^(1/4))/(10^(-1/5)xx5^(3/5))div(3^(4/3)xx5^(-7/5))/(4^(-3/5)xx6)=10`
If 2x = 3y = 6-z, show that `1/x+1/y+1/z=0`
Find the value of x in the following:
`2^(5x)div2x=root5(2^20)`
Find the value of x in the following:
`2^(x-7)xx5^(x-4)=1250`
Write the value of \[\sqrt[3]{125 \times 27}\].
If (23)2 = 4x, then 3x =
If \[4x - 4 x^{- 1} = 24,\] then (2x)x equals
The value of 64-1/3 (641/3-642/3), is
If \[2^{- m} \times \frac{1}{2^m} = \frac{1}{4},\] then \[\frac{1}{14}\left\{ ( 4^m )^{1/2} + \left( \frac{1}{5^m} \right)^{- 1} \right\}\] is equal to
