Advertisements
Advertisements
प्रश्न
Prove that:
`9^(3/2)-3xx5^0-(1/81)^(-1/2)=15`
Advertisements
उत्तर
we have to prove that `9^(3/2)-3xx5^0-(1/81)^(-1/2)=15`
`9^(3/2)-3xx5^0-(1/81)^(-1/2)=3^(2xx3/2)-3xx5^0-1/81^(-1/2)`
`=3^3-3xx1-1/(1/sqrt81)`
`=3^3-3-1/(1/root2(9xx9))`
`=27-3-1/(1/9)`
`=27-3-1xx9/1`
= 27 - 12
= 15
Hence `9^(3/2)-3xx5^0-(1/81)^(-1/2)=15`
APPEARS IN
संबंधित प्रश्न
Simplify the following:
`(5xx25^(n+1)-25xx5^(2n))/(5xx5^(2n+3)-25^(n+1))`
Assuming that x, y, z are positive real numbers, simplify the following:
`(sqrt2/sqrt3)^5(6/7)^2`
Simplify:
`((25)^(3/2)xx(243)^(3/5))/((16)^(5/4)xx(8)^(4/3))`
Show that:
`(3^a/3^b)^(a+b)(3^b/3^c)^(b+c)(3^c/3^a)^(c+a)=1`
Show that:
`((a+1/b)^mxx(a-1/b)^n)/((b+1/a)^mxx(b-1/a)^n)=(a/b)^(m+n)`
Which one of the following is not equal to \[\left( \sqrt[3]{8} \right)^{- 1/2} ?\]
If \[x = 7 + 4\sqrt{3}\] and xy =1, then \[\frac{1}{x^2} + \frac{1}{y^2} =\]
\[\frac{1}{\sqrt{9} - \sqrt{8}}\] is equal to
Simplify:
`11^(1/2)/11^(1/4)`
Which of the following is equal to x?
