Advertisements
Advertisements
प्रश्न
If a = 3 and b = -2, find the values of :
ab + ba
Advertisements
उत्तर
ab + ba
Here a = 3 and b = -2
Put the values in the expression ab + ba
3-2 + (-2)3
`=(1/3)^2+(-8)`
`=1/9-8`
`=(1-72)/9`
`=-71/9`
APPEARS IN
संबंधित प्रश्न
Simplify the following
`((4xx10^7)(6xx10^-5))/(8xx10^4)`
Prove that:
`(x^a/x^b)^(a^2+ab+b^2)xx(x^b/x^c)^(b^2+bc+c^2)xx(x^c/x^a)^(c^2+ca+a^2)=1`
If 49392 = a4b2c3, find the values of a, b and c, where a, b and c are different positive primes.
Prove that:
`(1/4)^-2-3xx8^(2/3)xx4^0+(9/16)^(-1/2)=16/3`
Solve the following equation:
`4^(x-1)xx(0.5)^(3-2x)=(1/8)^x`
For any positive real number x, write the value of \[\left\{ \left( x^a \right)^b \right\}^\frac{1}{ab} \left\{ \left( x^b \right)^c \right\}^\frac{1}{bc} \left\{ \left( x^c \right)^a \right\}^\frac{1}{ca}\]
The seventh root of x divided by the eighth root of x is
If \[\frac{x}{x^{1 . 5}} = 8 x^{- 1}\] and x > 0, then x =
If \[4x - 4 x^{- 1} = 24,\] then (2x)x equals
The value of 64-1/3 (641/3-642/3), is
