Advertisements
Advertisements
Question
Prove that:
`9^(3/2)-3xx5^0-(1/81)^(-1/2)=15`
Advertisements
Solution
we have to prove that `9^(3/2)-3xx5^0-(1/81)^(-1/2)=15`
`9^(3/2)-3xx5^0-(1/81)^(-1/2)=3^(2xx3/2)-3xx5^0-1/81^(-1/2)`
`=3^3-3xx1-1/(1/sqrt81)`
`=3^3-3-1/(1/root2(9xx9))`
`=27-3-1/(1/9)`
`=27-3-1xx9/1`
= 27 - 12
= 15
Hence `9^(3/2)-3xx5^0-(1/81)^(-1/2)=15`
APPEARS IN
RELATED QUESTIONS
Simplify:
`((5^-1xx7^2)/(5^2xx7^-4))^(7/2)xx((5^-2xx7^3)/(5^3xx7^-5))^(-5/2)`
If 2x = 3y = 6-z, show that `1/x+1/y+1/z=0`
If `5^(3x)=125` and `10^y=0.001,` find x and y.
Simplify:
`root(lm)(x^l/x^m)xxroot(mn)(x^m/x^n)xxroot(nl)(x^n/x^l)`
State the quotient law of exponents.
Which of the following is (are) not equal to \[\left\{ \left( \frac{5}{6} \right)^{1/5} \right\}^{- 1/6}\] ?
If a, b, c are positive real numbers, then \[\sqrt{a^{- 1} b} \times \sqrt{b^{- 1} c} \times \sqrt{c^{- 1} a}\] is equal to
If \[x = \sqrt{6} + \sqrt{5}\],then \[x^2 + \frac{1}{x^2} - 2 =\]
If \[\sqrt{13 - a\sqrt{10}} = \sqrt{8} + \sqrt{5}, \text { then a } =\]
If `a = 2 + sqrt(3)`, then find the value of `a - 1/a`.
