Advertisements
Advertisements
Question
Prove that:
`9^(3/2)-3xx5^0-(1/81)^(-1/2)=15`
Advertisements
Solution
we have to prove that `9^(3/2)-3xx5^0-(1/81)^(-1/2)=15`
`9^(3/2)-3xx5^0-(1/81)^(-1/2)=3^(2xx3/2)-3xx5^0-1/81^(-1/2)`
`=3^3-3xx1-1/(1/sqrt81)`
`=3^3-3-1/(1/root2(9xx9))`
`=27-3-1/(1/9)`
`=27-3-1xx9/1`
= 27 - 12
= 15
Hence `9^(3/2)-3xx5^0-(1/81)^(-1/2)=15`
APPEARS IN
RELATED QUESTIONS
Solve the following equation for x:
`2^(x+1)=4^(x-3)`
Show that:
`(x^(a^2+b^2)/x^(ab))^(a+b)(x^(b^2+c^2)/x^(bc))^(b+c)(x^(c^2+a^2)/x^(ac))^(a+c)=x^(2(a^3+b^3+c^3))`
Find the value of x in the following:
`(13)^(sqrtx)=4^4-3^4-6`
If a and b are different positive primes such that
`(a+b)^-1(a^-1+b^-1)=a^xb^y,` find x + y + 2.
If 3x-1 = 9 and 4y+2 = 64, what is the value of \[\frac{x}{y}\] ?
Write the value of \[\sqrt[3]{7} \times \sqrt[3]{49} .\]
When simplified \[\left( - \frac{1}{27} \right)^{- 2/3}\] is
If x= \[\frac{\sqrt{3} - \sqrt{2}}{\sqrt{3} + \sqrt{2}}\] and y = \[\frac{\sqrt{3} + \sqrt{2}}{\sqrt{3} - \sqrt{2}}\] , then x2 + y +y2 =
If \[\sqrt{2} = 1 . 414,\] then the value of \[\sqrt{6} - \sqrt{3}\] upto three places of decimal is
The positive square root of \[7 + \sqrt{48}\] is
