Advertisements
Advertisements
प्रश्न
Prove that:
`9^(3/2)-3xx5^0-(1/81)^(-1/2)=15`
Advertisements
उत्तर
we have to prove that `9^(3/2)-3xx5^0-(1/81)^(-1/2)=15`
`9^(3/2)-3xx5^0-(1/81)^(-1/2)=3^(2xx3/2)-3xx5^0-1/81^(-1/2)`
`=3^3-3xx1-1/(1/sqrt81)`
`=3^3-3-1/(1/root2(9xx9))`
`=27-3-1/(1/9)`
`=27-3-1xx9/1`
= 27 - 12
= 15
Hence `9^(3/2)-3xx5^0-(1/81)^(-1/2)=15`
APPEARS IN
संबंधित प्रश्न
Solve the following equation for x:
`4^(x-1)xx(0.5)^(3-2x)=(1/8)^x`
Simplify:
`((25)^(3/2)xx(243)^(3/5))/((16)^(5/4)xx(8)^(4/3))`
Prove that:
`((0.6)^0-(0.1)^-1)/((3/8)^-1(3/2)^3+((-1)/3)^-1)=(-3)/2`
Show that:
`(x^(1/(a-b)))^(1/(a-c))(x^(1/(b-c)))^(1/(b-a))(x^(1/(c-a)))^(1/(c-b))=1`
Show that:
`((a+1/b)^mxx(a-1/b)^n)/((b+1/a)^mxx(b-1/a)^n)=(a/b)^(m+n)`
The value of \[\left\{ \left( 23 + 2^2 \right)^{2/3} + (140 - 19 )^{1/2} \right\}^2 ,\] is
If g = `t^(2/3) + 4t^(-1/2)`, what is the value of g when t = 64?
If \[\frac{3^{5x} \times {81}^2 \times 6561}{3^{2x}} = 3^7\] then x =
The simplest rationalising factor of \[\sqrt{3} + \sqrt{5}\] is ______.
If `a = 2 + sqrt(3)`, then find the value of `a - 1/a`.
