Advertisements
Advertisements
प्रश्न
Show that:
`(x^(a-b))^(a+b)(x^(b-c))^(b+c)(x^(c-a))^(c+a)=1`
Advertisements
उत्तर
`(x^(a-b))^(a+b)(x^(b-c))^(b+c)(x^(c-a))^(c+a)=1`
LHS = `(x^(a-b))^(a+b)(x^(b-c))^(b+c)(x^(c-a))^(c+a)`
`=[x^((a-b)(a+b))][x^((b-c)(b+c))][x^((c-a)(c+a))]`
`=x^((a^2-b^2))x^((b^2-c^2))x^((c^2-a^2))`
`=x^(a^2-b^2+b^2-c^2+c^2-a^2)`
`=x^0`
= 1
= RHS
APPEARS IN
संबंधित प्रश्न
If a = 3 and b = -2, find the values of :
aa + bb
Given `4725=3^a5^b7^c,` find
(i) the integral values of a, b and c
(ii) the value of `2^-a3^b7^c`
If 2x = 3y = 12z, show that `1/z=1/y+2/x`
If 3x = 5y = (75)z, show that `z=(xy)/(2x+y)`
Simplify:
`root(lm)(x^l/x^m)xxroot(mn)(x^m/x^n)xxroot(nl)(x^n/x^l)`
If 102y = 25, then 10-y equals
If 9x+2 = 240 + 9x, then x =
If x is a positive real number and x2 = 2, then x3 =
If \[x = 7 + 4\sqrt{3}\] and xy =1, then \[\frac{1}{x^2} + \frac{1}{y^2} =\]
Which of the following is equal to x?
