Advertisements
Advertisements
प्रश्न
The value of \[\sqrt{5 + 2\sqrt{6}}\] is
पर्याय
\[\sqrt{3} - \sqrt{2}\]
\[\sqrt{3} + \sqrt{2}\]
\[\sqrt{5} + \sqrt{6}\]
none of these
Advertisements
उत्तर
Given that:`sqrt(5+2sqrt6)`.It can be written in the form `(a-b )^2 = a^2 +b^2 - 2 ab` as
`sqrt(5+2sqrt6) = sqrt(3+2+2xxsqrt3 xxsqrt2)`
` =sqrt((sqrt3)^2 + (sqrt2)^2+ 2 xx sqrt3 xxsqrt2)`
`= sqrt((sqrt3+sqrt2)^2)`
` = sqrt3 +sqrt2.`
APPEARS IN
संबंधित प्रश्न
Solve the following equation for x:
`4^(x-1)xx(0.5)^(3-2x)=(1/8)^x`
Simplify:
`((5^-1xx7^2)/(5^2xx7^-4))^(7/2)xx((5^-2xx7^3)/(5^3xx7^-5))^(-5/2)`
Prove that:
`(64/125)^(-2/3)+1/(256/625)^(1/4)+(sqrt25/root3 64)=65/16`
Show that:
`{(x^(a-a^-1))^(1/(a-1))}^(a/(a+1))=x`
If 3x = 5y = (75)z, show that `z=(xy)/(2x+y)`
If 1176 = `2^axx3^bxx7^c,` find the values of a, b and c. Hence, compute the value of `2^axx3^bxx7^-c` as a fraction.
Show that:
`((a+1/b)^mxx(a-1/b)^n)/((b+1/a)^mxx(b-1/a)^n)=(a/b)^(m+n)`
The value of m for which \[\left[ \left\{ \left( \frac{1}{7^2} \right)^{- 2} \right\}^{- 1/3} \right]^{1/4} = 7^m ,\] is
The value of \[\left\{ \left( 23 + 2^2 \right)^{2/3} + (140 - 19 )^{1/2} \right\}^2 ,\] is
Find:-
`125^(1/3)`
