Advertisements
Advertisements
प्रश्न
If \[\frac{5 - \sqrt{3}}{2 + \sqrt{3}} = x + y\sqrt{3}\] , then
पर्याय
x = 13, y = −7
x = −13, y = 7
x = −13, y =- 7
x = 13, y = 7
Advertisements
उत्तर
Given that:`(5-sqrt3)/(2+sqrt3) = x+ysqrt3`We need to find x and y
We know that rationalization factor for `2+sqrt3` is`2-sqrt3` . We will multiply numerator and denominator of the given expression `(5-sqrt3)/(2+sqrt3)`by, 2-sqrt3` to get
`(5-sqrt3)/(2+sqrt3) xx (2-sqrt3)/(2-sqrt2) = (5 xx 2 - 5 xx sqrt3 - 2 xx sqrt3 +(sqrt3)^3)/((2)^2 - (sqrt3)^2)`
` (10-5sqrt3 - 2 sqrt3 +3)/((2)^2 -(sqrt3)^2)`
` = (13-7sqrt3) /(4-3)`
` = 13 - 7sqrt3.`
Since ` x + y sqrt3 = 13 - 7 sqrt3`
On equating rational and irrational terms, we get `x=13 and y= -7`
APPEARS IN
संबंधित प्रश्न
Simplify the following
`3(a^4b^3)^10xx5(a^2b^2)^3`
Prove that:
`(x^a/x^b)^cxx(x^b/x^c)^axx(x^c/x^a)^b=1`
If `a=xy^(p-1), b=xy^(q-1)` and `c=xy^(r-1),` prove that `a^(q-r)b^(r-p)c^(p-q)=1`
Simplify:
`(sqrt2/5)^8div(sqrt2/5)^13`
If a and b are different positive primes such that
`(a+b)^-1(a^-1+b^-1)=a^xb^y,` find x + y + 2.
State the quotient law of exponents.
If \[2^{- m} \times \frac{1}{2^m} = \frac{1}{4},\] then \[\frac{1}{14}\left\{ ( 4^m )^{1/2} + \left( \frac{1}{5^m} \right)^{- 1} \right\}\] is equal to
If \[\sqrt{2} = 1 . 4142\] then \[\sqrt{\frac{\sqrt{2} - 1}{\sqrt{2} + 1}}\] is equal to
Find:-
`16^(3/4)`
Simplify:
`(9^(1/3) xx 27^(-1/2))/(3^(1/6) xx 3^(- 2/3))`
