Advertisements
Advertisements
प्रश्न
Show that:
`{(x^(a-a^-1))^(1/(a-1))}^(a/(a+1))=x`
Advertisements
उत्तर
`{(x^(a-a^-1))^(1/(a-1))}^(a/(a+1))=x`
LHS = `{(x^(a-a^-1))^(1/(a-1))}^(a/(a+1))`
`={(x^(a-1/a))^(1/(a-1)xxa/(a+1))}`
`={x^((a^2-1)/a)}^(a/(a^2-1))`
`=x^((a^2-1)/axxa/(a^2-1))`
`=x^1`
`= x`
= RHS
APPEARS IN
संबंधित प्रश्न
Prove that:
`(x^a/x^b)^cxx(x^b/x^c)^axx(x^c/x^a)^b=1`
Assuming that x, y, z are positive real numbers, simplify the following:
`(x^((-2)/3)y^((-1)/2))^2`
Find the value of x in the following:
`5^(2x+3)=1`
If `2^x xx3^yxx5^z=2160,` find x, y and z. Hence, compute the value of `3^x xx2^-yxx5^-z.`
Simplify:
`(x^(a+b)/x^c)^(a-b)(x^(b+c)/x^a)^(b-c)(x^(c+a)/x^b)^(c-a)`
If 24 × 42 =16x, then find the value of x.
If \[\sqrt{5^n} = 125\] then `5nsqrt64`=
If x = \[\frac{2}{3 + \sqrt{7}}\],then (x−3)2 =
If \[x + \sqrt{15} = 4,\] then \[x + \frac{1}{x}\] =
Find:-
`125^(1/3)`
