Advertisements
Advertisements
प्रश्न
Which one of the following is not equal to \[\left( \sqrt[3]{8} \right)^{- 1/2} ?\]
पर्याय
\[\sqrt[3]{2}^{- 1/2}\]
\[8^{- 1/6}\]
\[\frac{1}{(\sqrt[3]{8} )^{1/2}}\]
\[\frac{1}{\sqrt{2}}\]
Advertisements
उत्तर
We have to find the value of `(3sqrt8)^(-1/2)`
So,
`(3sqrt8)^(-1/2) = (3sqrt(2xx 2xx 2))^(-1/2)`
`=(3sqrt(2^3))^(1/2)`
`2^(3 xx 1/3 xx -1/2)`
`2^(3 xx 1/3 xx -1/2)`
`(3sqrt8)^(-1/2) = 2^(-1/2)`
`= 1/(2^(1/2))`
`= 1/sqrt2`
Also, `(sqrt8)^(-1/2) = 2 ^(-1/6)`
APPEARS IN
संबंधित प्रश्न
Simplify the following
`(2x^-2y^3)^3`
Prove that:
`1/(1+x^(a-b))+1/(1+x^(b-a))=1`
Assuming that x, y, z are positive real numbers, simplify the following:
`root5(243x^10y^5z^10)`
Simplify:
`(16^(-1/5))^(5/2)`
Simplify:
`(sqrt2/5)^8div(sqrt2/5)^13`
Find the value of x in the following:
`5^(x-2)xx3^(2x-3)=135`
If `3^(x+1)=9^(x-2),` find the value of `2^(1+x)`
If 1176 = `2^axx3^bxx7^c,` find the values of a, b and c. Hence, compute the value of `2^axx3^bxx7^-c` as a fraction.
If `a=x^(m+n)y^l, b=x^(n+l)y^m` and `c=x^(l+m)y^n,` Prove that `a^(m-n)b^(n-l)c^(l-m)=1`
If a, b, c are positive real numbers, then \[\sqrt[5]{3125 a^{10} b^5 c^{10}}\] is equal to
