Advertisements
Advertisements
प्रश्न
When simplified \[\left( - \frac{1}{27} \right)^{- 2/3}\] is
पर्याय
9
-9
\[\frac{1}{9}\]
\[- \frac{1}{9}\]
Advertisements
उत्तर
We have to find the value of `(-1/27)^((-2)/3)`
So,
`(-1/27)^((-2)/3)` = `(-1/27)^((-2)/3)`
`= (-1/3^3)^((-2)/3)`
` = -1/(3^(3x(-2)/3`
` = -1/(3^(3x(-2)/3`
`(-1/27)^((-2)/3) = -1/3^-2`
`-1/(1/(3^2))`
`-1/(1/9)`
= 9
APPEARS IN
संबंधित प्रश्न
Simplify the following
`((4xx10^7)(6xx10^-5))/(8xx10^4)`
Prove that:
`(a^-1+b^-1)^-1=(ab)/(a+b)`
Given `4725=3^a5^b7^c,` find
(i) the integral values of a, b and c
(ii) the value of `2^-a3^b7^c`
Assuming that x, y, z are positive real numbers, simplify the following:
`sqrt(x^3y^-2)`
Assuming that x, y, z are positive real numbers, simplify the following:
`(sqrtx)^((-2)/3)sqrt(y^4)divsqrt(xy^((-1)/2))`
Simplify:
`(16^(-1/5))^(5/2)`
Show that:
`(x^(a-b))^(a+b)(x^(b-c))^(b+c)(x^(c-a))^(c+a)=1`
Which one of the following is not equal to \[\left( \sqrt[3]{8} \right)^{- 1/2} ?\]
If \[x = 7 + 4\sqrt{3}\] and xy =1, then \[\frac{1}{x^2} + \frac{1}{y^2} =\]
If x = \[\sqrt[3]{2 + \sqrt{3}}\] , then \[x^3 + \frac{1}{x^3} =\]
