Advertisements
Advertisements
प्रश्न
The product of the square root of x with the cube root of x is
पर्याय
cube root of the square root of x
sixth root of the fifth power of x
fifth root of the sixth power of x
sixth root of x
Advertisements
उत्तर
We have to find the product (say L) of the square root of x with the cube root of x is. So,
`L = 2sqrtx xx 3sqrtx`
`= x^(1/2) xx x ^(1/3)`
`= x^(1/2+1/3)`
`= x^((1xx3)/(2xx3)+(1xx2)/(3xx2))`
\[= x^\frac{3 + 2}{6} = x^\frac{5}{6}\]
The product of the square root of x with the cube root of x is `x^(5/6)`
Hence the correct alternative is b.
APPEARS IN
संबंधित प्रश्न
Find:-
`9^(3/2)`
If a = 3 and b = -2, find the values of :
(a + b)ab
Given `4725=3^a5^b7^c,` find
(i) the integral values of a, b and c
(ii) the value of `2^-a3^b7^c`
Simplify:
`(16^(-1/5))^(5/2)`
If `27^x=9/3^x,` find x.
If a, b, c are positive real numbers, then \[\sqrt{a^{- 1} b} \times \sqrt{b^{- 1} c} \times \sqrt{c^{- 1} a}\] is equal to
If x = 2 and y = 4, then \[\left( \frac{x}{y} \right)^{x - y} + \left( \frac{y}{x} \right)^{y - x} =\]
If g = `t^(2/3) + 4t^(-1/2)`, what is the value of g when t = 64?
If \[\frac{3^{2x - 8}}{225} = \frac{5^3}{5^x},\] then x =
The positive square root of \[7 + \sqrt{48}\] is
