Advertisements
Advertisements
प्रश्न
The seventh root of x divided by the eighth root of x is
पर्याय
x
\[\sqrt{x}\]
\[\sqrt[56]{x}\]
\[\frac{1}{\sqrt[56]{x}}\]
Advertisements
उत्तर
We have to find he seventh root of x divided by the eighth root of x, so let it be L. So,
`L= (7sqrtx)/(8sqrtx)`
`= (x^(1/7))/(x^(1/8))`
`= x^(1/7-1/8)`
`= x^((1xx8)/(7xx8)-(1 xx7) /(8 xx 7))`
`L = x^(8/56 -7/56)`
`=x^1/56`
`=56sqrtx`
The seventh root of x divided by the eighth root of x is `56sqrtx`
Hence the correct choice is c.
APPEARS IN
संबंधित प्रश्न
Prove that:
`(a+b+c)/(a^-1b^-1+b^-1c^-1+c^-1a^-1)=abc`
Simplify:
`(0.001)^(1/3)`
Show that:
`[{x^(a(a-b))/x^(a(a+b))}div{x^(b(b-a))/x^(b(b+a))}]^(a+b)=1`
Find the value of x in the following:
`5^(x-2)xx3^(2x-3)=135`
If a and b are different positive primes such that
`((a^-1b^2)/(a^2b^-4))^7div((a^3b^-5)/(a^-2b^3))=a^xb^y,` find x and y.
State the quotient law of exponents.
State the power law of exponents.
If \[x = 7 + 4\sqrt{3}\] and xy =1, then \[\frac{1}{x^2} + \frac{1}{y^2} =\]
The value of \[\sqrt{5 + 2\sqrt{6}}\] is
If \[\sqrt{13 - a\sqrt{10}} = \sqrt{8} + \sqrt{5}, \text { then a } =\]
